Non-consuming Regular Expression Split In Python

How can a string be split on a separator expression while leaving that separator on the preceding string? >>> text = 'This is an example. Is it made up of more than once s

Solution 1:

>>> re.split("(?<=[\.\?!]) ", text)
['This is an example.', 'Is it made up of more than once sentence?', 'Yes, it is.']

The crucial thing is the use of a look-behind assertion with ?<=.

Solution 2:

import re

text = "This is an example.A particular case.Made up of more "\
       "than once sentence?Yes, it is.But no blank !!!That's"\
       " a problem ????Yes.I think so! :)"for x in re.split("(?<=[\.\?!]) ", text):
    printrepr(x)

print'\n'for x in re.findall("[^.?!]*[.?!]|[^.?!]+(?=\Z)",text):
    printrepr(x)

result

"This is an example.A particular case.Made up of more than once sentence?Yes, it is.But no blank !!!That'sa problem ????Yes.I think so!"':)''This is an example.''A particular case.''Made up of more than once sentence?''Yes, it is.''But no blank !''!''!'"That's a problem ?"'?''?''?''Yes.''I think so!'' :)'

.

EDIT

Also

import re

text = "! This is an example.A particular case.Made up of more "\
       "than once sentence?Yes, it is.But no blank !!!That's"\
       " a problem ????Yes.I think so! :)"

res = re.split('([.?!])',text)

print [ ''.join(res[i:i+2]) for i in xrange(0,len(res),2) ]

gives

['!', ' This is an example.', 'A particular case.', 'Made up of more than once sentence?', 'Yes, it is.', 'But no blank !', '!', '!', "That's a problem ?", '?', '?', '?', 'Yes.', 'I think so!', ' :)']