Built-in Variable To Get Current Function
I have a lot of functions like the following, which recursively call themselves to get one or many returns depending on the type of the argument: def get_data_sensor(self, sensorna
Solution 1:
You can abstract that logic outside the function entirely by using a decorator (see this thorough answer if you're unfamiliar with decorators):
from functools import wraps
defautolist(func):
@wraps(func)defwrapper(args):
ifisinstance(args, list):
return [func(arg) for arg in args]
return func(args)
return wrapper
This decorator can be applied to any function requiring the pattern, which now only needs to implement the scalar case:
>>>@autolist...defsquare(x):...return x ** 2...>>>square(1)
1
>>>square([1, 2, 3])
[1, 4, 9]
If you're applying it to a method, as self
implies, you'll also need to take that argument into account in the wrapper
. For example, if the relevant argument is always the last one you could do:
defautolist(func):
@wraps(func)defwrapper(*args):
*args, last_arg = args
ifisinstance(last_arg, list):
return [func(*args, arg) for arg in last_arg]
return func(*args, last_arg)
return wrapper
This would work on methods, too:
>>>classSquarer:... @autolist...defsquare(self, x):...return x ** 2...>>>Squarer().square(1)
1
>>>Squarer().square([1, 2, 3])
[1, 4, 9]
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