Python Print Out Float Or Integer

How can i print out float if the result have decimal or print out integer if the result have no decimal? c = input('Enter the total cost of purchase: ') bank = raw_input('Enter the

Solution 1:

You can try this, which simply uses Python's string formatting method:

if int(c) == float(c):
    decimals = 0
else:
    decimals = 2 # Assumes 2 decimal places for money

print('Please pay: ${0:.{1}f}'.format(c, decimals))

This will give you the following output if c == 1.00:

Please pay: $1

Or this output if c == 20.56:

Please pay: $20.56

Solution 2:

Python floats have a built-in method to determine whether they're an integer:

x = 212.50
y = 212.0
f = lambda x: int(x) if x.is_integer() else x
print(x, f(x), y, f(y), sep='\t')
>> 212.5    212.5   212.0   212

Solution 3:

Since there is a much simpler way now and this post is the first result, people should now about it:

print(f"{3.0:g}")  # 3
print(f"{3.14:g}")  # 3.14

Solution 4:

def nice_print(i):
    print '%.2f' % i if i - int(i) != 0 else '%d' % i

nice_print(44)
44

nice_print(44.345)
44.34

in Your code:

def nice_number(i):
    return '%.2f' % i if i - int(i) != 0 else '%d' % i

c = input("Enter the total cost of purchase: ")
bank = raw_input("Enter the bank of your credit card (DBS, OCBC, etc.): ")
dbs1 = ((c/float(100))*10)
dbs2 = c-dbs1
ocbc1 = ((c/float(100))*15)
ocbc2 = c-ocbc1


if (c > 200):
    if (bank == 'DBS'):
        print('Please pay $'+nice_number(dbs2))
    elif (bank == 'OCBC'):
        print('Please pay $'+nice_number(ocbc2))
    else:
        print('Please pay $'+nice_number(c))
else:
    print('Please pay $'+nice_number(c))